"""
* Assignment: Sequence Slice Header/Rows
* Required: yes
* Complexity: easy
* Lines of code: 2 lines
* Time: 3 min

English:
    1. Separate header (first line) from rows:
       a. Define `header: tuple[str]` with header
       b. Define `rows: list[tuple]` with other rows
    2. Run doctests - all must succeed

Polish:
    1. Odseparuj nagłówek (pierwsza linia) od danych:
       a. Zdefiniuj `header: tuple[str]` z nagłówkiem
       b. Zdefiniuj `rows: list[tuple]` z pozostałymi wierszami
    2. Uruchom doctesty - wszystkie muszą się powieść

Tests:
    >>> import sys; sys.tracebacklimit = 0

    >>> assert header is not Ellipsis, \
    'Assign your result to variable `header`'
    >>> assert rows is not Ellipsis, \
    'Assign your result to variable `rows`'
    >>> assert type(header) is tuple, \
    'Variable `header` has invalid type, should be tuple'
    >>> assert all(type(x) is tuple for x in rows), \
    'All elements in `rows` should be tuple'
    >>> assert header not in rows, \
    'Header should not be in `rows`'

    >>> header
    ('Sepal length', 'Sepal width', 'Petal length', 'Petal width', 'Species')

    >>> rows  # doctest: +NORMALIZE_WHITESPACE
    [(5.8, 2.7, 5.1, 1.9, 'virginica'),
     (5.1, 3.5, 1.4, 0.2, 'setosa'),
     (5.7, 2.8, 4.1, 1.3, 'versicolor'),
     (6.3, 2.9, 5.6, 1.8, 'virginica'),
     (6.4, 3.2, 4.5, 1.5, 'versicolor'),
     (4.7, 3.2, 1.3, 0.2, 'setosa'),
     (7.0, 3.2, 4.7, 1.4, 'versicolor'),
     (7.6, 3.0, 6.6, 2.1, 'virginica'),
     (4.9, 3.0, 1.4, 0.2, 'setosa'),
     (4.9, 2.5, 4.5, 1.7, 'virginica')]
"""

DATA = [
    ('Sepal length', 'Sepal width', 'Petal length', 'Petal width', 'Species'),
    (5.8, 2.7, 5.1, 1.9, 'virginica'),
    (5.1, 3.5, 1.4, 0.2, 'setosa'),
    (5.7, 2.8, 4.1, 1.3, 'versicolor'),
    (6.3, 2.9, 5.6, 1.8, 'virginica'),
    (6.4, 3.2, 4.5, 1.5, 'versicolor'),
    (4.7, 3.2, 1.3, 0.2, 'setosa'),
    (7.0, 3.2, 4.7, 1.4, 'versicolor'),
    (7.6, 3.0, 6.6, 2.1, 'virginica'),
    (4.9, 3.0, 1.4, 0.2, 'setosa'),
    (4.9, 2.5, 4.5, 1.7, 'virginica')]


# Tuple with row at index 0 from DATA
# type: tuple[str]
header = ...

# List with rows at all the other indexes from DATA
# type: list[tuple]
rows = ...

# Solution
header = DATA[0]
rows = DATA[1:]